Two particles having position vectors →r1=(3^i+5^j) m and →r2=(−5^i+3^j) m are moving with velocities →v1=(4^i−4^j) ms−1 and →v2=(a^i−3^j) ms−1. If they collide after 2 s, the value of the constant 'a' is

Two particles having position vectors →r1=(3^i+5^j) m and →r2=(−

1.	Two particles having position vectors →r1=(3^i+5^j) m and →r2=(−5^i+3^j) m are moving with velocities →v1=(4^i−4^j) ms−1 and →v2=(a^i−3^j) ms−1. If they collide after 2 s, the value of the constant 'a' is
Answer» Two particles having position vectors $_{1} = (3^i + 5^j) m$ and $_{2} = (- 5^i + 3^j) m$ are moving with velocities $_{1} = (4^i - 4^j) {ms}^{- 1}$ and $_{2} = (a^i - 3^j) {ms}^{- 1}$ . If they collide after $2 s$ , the value of the constant ' $a$ ' is

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Two particles having position vectors →r1=(3^i+5^j) m and →r2=(−5^i+3^j) m are moving with velocities →v1=(4^i−4^j) ms−1 and →v2=(a^i−3^j) ms−1. If they collide after 2 s, the value of the constant 'a' is

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