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Two particles having position vectors `vecr_(1)=(3veci+5 vecj)m` and `vecr_(2)=(-5veci+3 vecj)m` are moving with velocities `vecV_(1)=(4hati-4hatj)ms^(-1)` and `vecV_(2)=(1hati-3hatj)ms^(-1)`. If they collide after `2 ` seconds, the value of `a` isA. `2`B. `4`C. `6`D. `8` |
Answer» Correct Answer - C `vecr_(1)+vecv_(1)t=vecr_(2)+vecv_(2)t` |
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