Two particles move along x axis. the position of particle 1 is given by x = 6.00t2 + 3.00t + 2.00 (in meters and seconds); the acceleration of particle 2 is given by a = -8.00t ( in meters per second squared and seconds) and, at t = 0, its velocity is 19 m/s. When the velocities of the particles match, what is their velocity?

Two particles move along x axis. the position of particle 1 is given

1.	Two particles move along x axis. the position of particle 1 is given by x = 6.00t2 + 3.00t + 2.00 (in meters and seconds); the acceleration of particle 2 is given by a = -8.00t ( in meters per second squared and seconds) and, at t = 0, its velocity is 19 m/s. When the velocities of the particles match, what is their velocity?
Answer» Two particles move along x axis. the position of particle 1 is given by x = 6.00 $t^{2}$ + 3.00t + 2.00 (in meters and seconds); the acceleration of particle 2 is given by a = -8.00t ( in meters per second squared and seconds) and, at t = 0, its velocity is 19 m/s. When the velocities of the particles match, what is their velocity?

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