Two particles move in a uniform gravitational field with an acceleration "g". At the initial moment the particles were located at same point and moved with velocities u_(1) = 0.8 ms^(-1) and u_(2) = 4.0 ms^(-1) horizontally in opposite directions. Find the distance between the particles at the moment when their velocity vectors become mutually perpendicular. (g = 10 ms^(-2))

Two particles move in a uniform gravitational field with an accelerati

1.	Two particles move in a uniform gravitational field with an acceleration "g". At the initial moment the particles were located at same point and moved with velocities u_(1) = 0.8 ms^(-1) and u_(2) = 4.0 ms^(-1) horizontally in opposite directions. Find the distance between the particles at the moment when their velocity vectors become mutually perpendicular. (g = 10 ms^(-2))
Answer» Solution :`t = sqrt((u_(1)u_(2))/(G)), X = (u_(1) + u_(2))t`