1.

Two particles move in a uniform gravitational field with an acceleration `g`.At the initial moment the particles were located at same point and moved with velocities `u_(1)=9 ms^(-1)` and `u_(2)=4 ms^(-1)` horizontally in opposite directions.The time between the particles at the moment when their velocity vectors are mutually perpendicular in `s` in (take `g=10 ms^(-2)`)A. `0.36`B. `3.6`C. `0.6`D. 6

Answer» Correct Answer - C
`t=sqrt(u_(1)u_(2))/g`


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