Two particles of charge `q_(1)` and `q_(2)` are separated by distance `d` as shown in figure. Chrage `q_(1)` is situarted at the origin. The net electirc field due to the particles is zero at `x = d//4`. With `V = 0` at infinity, the location of a point in terms of `d` on the `x` axis (other at infinfity) at which the elctrical potential due to the two particles is zero, is given by: A. d/4B. 16dC. `-16 d`D. no point on the axis

Two particles of charge `q_(1)` and `q_(2)` are separated by distance

1.	Two particles of charge `q_(1)` and `q_(2)` are separated by distance `d` as shown in figure. Chrage `q_(1)` is situarted at the origin. The net electirc field due to the particles is zero at `x = d//4`. With `V = 0` at infinity, the location of a point in terms of `d` on the `x` axis (other at infinfity) at which the elctrical potential due to the two particles is zero, is given by: A. d/4B. 16dC. `-16 d`D. no point on the axis
Answer» Correct Answer - D `vec(E)` is zero in between the two charges. So both charges must have the same sign. Therefore, electric potential cannot be zero anywhere on the axis.

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