Two particles of equal mass m go round a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is

Two particles of equal mass m go round a circle of radius R under the

1.	Two particles of equal mass m go round a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is
Answer» `v=sqrt((1)/(GM))` `v=sqrt((4GM)/(R))` `v=(1)/(2)sqrt((GM)/(R))` `v=(1)/(2R)sqrt((1)/(GM))` SOLUTION :Centripetal force is provided by the gravitational force of attraction between TWO particles. i.e.,`(mv^2)/(R)=(GMxxm)/((2R)^(2))` `rArrv=(1)/(2)sqrt((GM)/(R))`