1.

Two particles of masses 1.0 kg and 2.0 kg are placed at a separation of 50cm. Assuming that only gravitational forces acting on the particles mutually , the initial acceleration of the first particle.

Answer»

SOLUTION :Gravitational force between the two PARTICLES
`F = (Gm_(1)m_2)/r^2`
`F = (6.67xx10^(-11)xx1xx2)/((0.5)^2)=5.3xx10^(-10)N`
The acceleration of 1.0 Kg PARTICLE is
`a_(1)=F/m_1=(5.3 xx10^(-10))/1=5.3xx10^(-10)m//s^2`
It is towards the 2.0 Kg particle.


Discussion

No Comment Found