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Two particles of masses 1.0 kg and 2.0 kg are placed at a separation of 50cm. Assuming that only gravitational forces acting on the particles mutually , the initial acceleration of the first particle. |
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Answer» SOLUTION :Gravitational force between the two PARTICLES `F = (Gm_(1)m_2)/r^2` `F = (6.67xx10^(-11)xx1xx2)/((0.5)^2)=5.3xx10^(-10)N` The acceleration of 1.0 Kg PARTICLE is `a_(1)=F/m_1=(5.3 xx10^(-10))/1=5.3xx10^(-10)m//s^2` It is towards the 2.0 Kg particle. |
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