Two particles of masses 1 kg and 3 kg have position vectors 2hati+3hatj+4hatk and -2 hati +3 hatj-4hatk respectively. The centre of mass has a position vector

Two particles of masses 1 kg and 3 kg have position vectors 2hati+3hat

1.	Two particles of masses 1 kg and 3 kg have position vectors 2hati+3hatj+4hatk and -2 hati +3 hatj-4hatk respectively. The centre of mass has a position vector
Answer» `hati + 3hatj - 2hatk` `-hati - 3 hatj - 2hatk` `-hati + 3hatj + 2hatk` `-hati + 3hatj - 2hatk` SOLUTION :Here `m_(1) = 1` KG , `m_(2) =` 3 kg `vecr_(1) = 2hati +3hatj + 4hatk , vecr_(2) = -2hati + 3hatj - 4hatk` The POSITION vector of CENTRE of MASS is `vecR_(CM) = (m_(1) vecr_(1) + m_(2) vecr_(2))/(m_(1) + m_(2)) = ((1) (2 hati + 3hatj + 4hatk) + (3) (-2hati + 3hatj - 4hatk))/(1 + 3)` `= (2 hati + 3hatj + 4hatk - 6hati + 9hatj - 12 hatk)/(4) = (-4hati + 12hatj - 8hatk)/(4) = - hati + 3hatj - 2hatk`