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Two particles of masses 2 kg and 4 kg are approaching towards each other with ccelerations 1m//s^(2) and 2m//s^(2), respectively, on a smooth horizontal suface. Then find the acceleration of centre of mass of the system and direction of acceleration of CM.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The acceleration of CM of the <a href="https://interviewquestions.tuteehub.com/tag/system-1237255" style="font-weight:bold;" target="_blank" title="Click to know more about SYSTEM">SYSTEM</a> is given by <br/> `a_(CM)=(m_(1)a_(1)+m_(2)a_(2))/(m_(2)+m_(2))impliesa_(CM)=(2xx1+<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>(-2))/(2+4)=-1m//s^(2)` <br/> Negative sign indicates that aceleratioin of CM will be in the direction of acceleration of `4 kg` mass.</body></html>


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