Two particles of masses m_(1) and m_(2) in projectile motion have velocities bar(v)_(1) and bar(v)_(2) respectively at time t = 0. They collide at time t_(0). Their velocities become vec(v)_(1)^(1) and vec(v)_(2)^(1) at time 2t_(0) while still moving in air. The value of |(m_(1)vec(v)_(1)^(1) + m_(2) vec(v)_(1)^(1)) - (m_(1) vec(v)_(1) + m_(2) vec(v)_(2))| is

Two particles of masses m_(1) and m_(2) in projectile motion have velo

1.	Two particles of masses m_(1) and m_(2) in projectile motion have velocities bar(v)_(1) and bar(v)_(2) respectively at time t = 0. They collide at time t_(0). Their velocities become vec(v)_(1)^(1) and vec(v)_(2)^(1) at time 2t_(0) while still moving in air. The value of \|(m_(1)vec(v)_(1)^(1) + m_(2) vec(v)_(1)^(1)) - (m_(1) vec(v)_(1) + m_(2) vec(v)_(2))\| is
Answer» zero `(m_(1) + m_(2)) G t_(0)` `2(m_(1) + m_(2))g t_(0)` `(1)/(2)(m_(1) + m_(2)) g t_(0)` ANSWER :C