Two particles of masses m_(1)and m_2 in projectile motion have velocities vecv_(1)and vecv_(2)respectively at time t = 0. They collide at time t_(0). Their velocities become vecv_(1) and vecv_(2) at time 2t_(0) while still moving in air. The value of |(m_(1)vecv_(1) + m_(2)vecv_(2)) -(m_(1)vecv_(1) + m_(2)vecv_(2))| is

Two particles of masses m_(1)and m_2 in projectile motion have velocit

1.	Two particles of masses m_(1)and m_2 in projectile motion have velocities vecv_(1)and vecv_(2)respectively at time t = 0. They collide at time t_(0). Their velocities become vecv_(1) and vecv_(2) at time 2t_(0) while still moving in air. The value of \|(m_(1)vecv_(1) + m_(2)vecv_(2)) -(m_(1)vecv_(1) + m_(2)vecv_(2))\| is
Answer» ZERO `(m_1+m_2) "gt"_0` `2(m_1+m_2)"gt"_0` `1/2 (m_1 + m_2) "gt"_0` ANSWER :C