Two particles of masses m_1 and m_2in projectile motion have velocities vecv_1 and vecv_2respectively at time t = 0. They collide at time t_0 . Their velocities become vecv_1^2 and vecv_2^1at time 2t_0while still moving in air. The value of |(m_1 vecv_1^1 + m_2vec_2^1) - (m_1vecv_1 + m_2vecv_2)|is

Two particles of masses m_1 and m_2in projectile motion have velocitie

1.	Two particles of masses m_1 and m_2in projectile motion have velocities vecv_1 and vecv_2respectively at time t = 0. They collide at time t_0 . Their velocities become vecv_1^2 and vecv_2^1at time 2t_0while still moving in air. The value of \|(m_1 vecv_1^1 + m_2vec_2^1) - (m_1vecv_1 + m_2vecv_2)\|is
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a><br/>`(m_1+m_2) "<a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a>"_0` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>(m_1+m_2)"gt"_0` <br/>`1/2 (m_1 + m_2) "gt"_0` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html>