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Two particles of masses `m` and `2m` have equal kinetic energies. Their de Broglie wavelengths area in the ratio of:A. `1:1`B. `1:2`C. `1:sqrt2`D. `sqrt2:1` |
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Answer» Correct Answer - D `because lambda=h/sqrt(2mK) K`.=kinetic energy `rArr lambda_(1)/lambda_(2)=sqrt(m_(2)k_(2))/sqrt(m_(1)k_(1))=sqrt(m_(2)/m_(1))=sqrt2/1` |
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