Two particles , one with constant velocity ` 50 m//s` and the other with uniform acceleration ` 10 m//s^(-2)`. Start moving simultaneously from the same place in the same direction. They will be at a distance of `125m` other after.A. (a) ` 5 sec`B. (b) ` 5 (1 + sqrt 2) sec`C. (c ) 10 sec`D. (d) ` 10 (sqrt 2 + 1) sec`

Two particles , one with constant velocity ` 50 m//s` and the other wi

1.	Two particles , one with constant velocity ` 50 m//s` and the other with uniform acceleration ` 10 m//s^(-2)`. Start moving simultaneously from the same place in the same direction. They will be at a distance of `125m` other after.A. (a) ` 5 sec`B. (b) ` 5 (1 + sqrt 2) sec`C. (c ) 10 sec`D. (d) ` 10 (sqrt 2 + 1) sec`
Answer» Correct Answer - C For particle `1` moving with constant velocity , ` S_1 = 50 t`. For particle `2` moving with constant acceleration, ` S_2 = 1/2 at^2 = 1/2 xx 10t^2 = 5t^2 , As per question , ltbRgt ` S-2 - S_1 = 12 5` or ` 5 t^2 - 50 t= 125` or ` t^2 - 10 t- 25 =0` On solving we ger,` t= (5 +-5 sqrt 2 ) sec. ` t=(5+5 sqrt 2) sec`.

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