Two particles P and Q are moving with velocities of (^i+^j) and (−^i+2^j) respectively. At time t=0, P is at origin and Q is at point with position vector (2^i+^j). The equation of the path of Q with respect to P is x+2y=c. Find the value of c

Two particles P and Q are moving with velocities of (^i+^j) and (−^i

1.	Two particles P and Q are moving with velocities of (^i+^j) and (−^i+2^j) respectively. At time t=0, P is at origin and Q is at point with position vector (2^i+^j). The equation of the path of Q with respect to P is x+2y=c. Find the value of c
Answer» Two particles $P$ and $Q$ are moving with velocities of $(^i +^j)$ and $(-^i + 2^j)$ respectively. At time $t = 0$ , $P$ is at origin and $Q$ is at point with position vector $(2^i +^j)$ . The equation of the path of $Q$ with respect to $P$ is $x + 2 y = c$ . Find the value of $c$

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Two particles P and Q are moving with velocities of (^i+^j) and (−^i+2^j) respectively. At time t=0, P is at origin and Q is at point with position vector (2^i+^j). The equation of the path of Q with respect to P is x+2y=c. Find the value of c

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