Two particles P and Q of mass 1 kg and 3 kg respectively start moving towards each other form rest under mutual attraction. What is the velocity of their center of mass ?

Two particles P and Q of mass 1 kg and 3 kg respectively start moving

1.	Two particles P and Q of mass 1 kg and 3 kg respectively start moving towards each other form rest under mutual attraction. What is the velocity of their center of mass ?
Answer» SOLUTION :MASS of first particle P is `m_(1)=1kg` Mass of second particle Q is `m_(2)=3kg` Velocity of particle P `=` Velocity of particle Q but in OPPOSITE Q but in opposite direction `:.` Velocity of centre of mass `v_(cm)=(m_(1)v_(1)+m_(2)v_(2))/(m_(1)+m_(2))` `=0`