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Two particles P and Q of mass 1 kg and 3 kg respectively start moving towards each other form rest under mutual attraction. What is the velocity of their center of mass ? |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of first particle P is `m_(1)=1kg` <br/> Mass of second particle Q is <br/>`m_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)=3kg` <br/>Velocity of particle P `=` Velocity of particle Q but in <a href="https://interviewquestions.tuteehub.com/tag/opposite-1137237" style="font-weight:bold;" target="_blank" title="Click to know more about OPPOSITE">OPPOSITE</a> Q but in opposite direction <br/> `:.` Velocity of centre of mass `v_(cm)=(m_(1)v_(1)+m_(2)v_(2))/(m_(1)+m_(2))` <br/> `=0`</body></html> | |