InterviewSolution
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InterviewSolution
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Two perfect gases at absolute temperature `T_(1) and T_(2)` are mixed. There is no loss of energy. The masses of the molecules are `m_(1) and m_(2)`. The number of molecules in the gases are `n_(1) and n_(2)`. The temperature of the mixture is |
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Answer» Before mixing, kinetic energy of all the molecules of two gases `= 3/2 kn_(1)T_(1)+3/2 kn_(2) T_(2)` If T is temperature of the mixuture , the average Ke of all molecules of two gases `= 3/2 k(n_(1)+n_(2))T = 32 k(n_(1)T_(1)+n_(2)T_(2))` `T=(n_(1)T_(1)+n_(2)T_(2))/(n_(1)+n_(2))`. |
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