Two perfect gasesat temperatures T_1 and T_2are mixed. There is no loss of energy. Find the temperature of mixture if messesof molecules are m and m and the number of molecules in the gases are n_1 and n_2respectively.

Two perfect gasesat temperatures T_1 and T_2are mixed. There is no los

1.	Two perfect gasesat temperatures T_1 and T_2are mixed. There is no loss of energy. Find the temperature of mixture if messesof molecules are m and m and the number of molecules in the gases are n_1 and n_2respectively.
Answer» Solution :Before mixing , KINETIC energy of all the molecules of TWO gases `3/2kn_1T1+3/2kn_2T_2` If the is temperature of the MIXTURE, the AVERAGE kinetic energy of all molecules of two gases `3/2k(n_1+n_2)T` As there is no loss of energy, THEREFORE, `3/2k(n_1+n_2)T=3/2k(n_1R_1+n_2T_2)` `T=(n_1T_1+n_2T_2)/(n_1+n_2)`