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Two perfectly elastic spheres of masses 2 kg and 3 kg moving in opposite directions with velocities 8 ms^(-1) and 6 ms^(-1) respectively colide with each other. Find their velocities after the impact. |
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Answer» SOLUTION :Here `m_(1) = 2kg, m_(2) = 3kg` `u_(1) 8ms^(-1), u_(2) = -6ms^(-1)` According to the law of conservation of LINEAR momentum. `m_(1)u_(1)+m_(2)u_(2)=m_(1)v_(1)+m_(2)v_(2)` i.e., `(2)(8) + (3) (-6) = 2v_(1) + 3v_(2)` `rArr2v_(1)+3v_(2)=-2 "" .....(i)` Since the collision is elastic, `u_(1) - U _(2) = v_(2) - v_(1)` i.e., `8 - (-6) = v_(2) - v_(1)` `rArr v_(2) - v_(1) = 14 "" .....(ii)` On solving the equations (i) and (ii) we get `v_(1) = - 8.8 MS^(-1), v_(2) = 5.2ms^(-1)` |
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