1.

Two perfectly elastic spheres of masses 2kg and 3kg moving in opposite directions with velocities 8 ms^(-1) and 6 ms^(-1) respectively collide with each other. Find their velocities after the impact

Answer»

Solution :Here `m_(1)= 2KG, m_(2)= 3kg`
`u_(1)= 8ms^(-1), u_(2)= -6 ms^(-1)`
According to the law of conservation of LINEAR momentum
`m_(1)u_(1) + m_(2)u_(2)- m_(1)v_(1) + m_(2)v_(2)`
i.e., `(2)(8) + (3) (-6) = 2v_(1) + 3v_(2)`
`rArr 2v_(1) + 3v_(2) = -2` ....(i)
SINCE the collision is elastic, `u_(1)-u_(2)= v_(2)-v_(1)`
i.e., `8-(-6)= v_(2)-v_(1)`
`rArr v_(2)-v_(1)= 14` ...(ii)
On SOLVING the equations (i) and (ii) we get
`v_(1)= -8.8 ms^(-1), v_(2)= 5.2 ms^(-1)`


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