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Two person A and B have 16 and 15 fair coin respectively. If both of them tosses all the coin then probability that A gets more head than B is p then the value of 16p is |
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Answer» i.e. 15 coins `P_(A)` = probability that A OBTAINS more heads than B `P_(B)` = probability that B obtains more heads than A `P_(D)` = probability that A obtains as many heads as B Such that `P_(A) + P_(B) +P_(D) = 1` ...(i) DUE to symmetry `P_(A) = P_(B)` as both FLIP equal number of coins. Now 'A' flips extra coin (`16^(TH)` coin). If it gives tail then does not contribute but if it gives HEAD then A gets more head than B required probability = `P_(A) + 1/2.P_(D)` `=P_(A) + 1/(2)(1-P_(A)-P_(B)) = 1/2`. |
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