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Two person pull a rope towards themselves. Each person exerts a force of 100 N on the rope. Find the Young modulus of the material of the rope if it extends in length by 1 cm. Original length of the rope=2 m and the area of cross section =cm^2.A. `10^(5)N//m^(2)`B. `10^(6)N//m^(2)`C. `10^(7)N//m^(2)`D. `10^(8)N//m^(2)` |
Answer» Correct Answer - D `y=(FL)/(Al) =(100xx2)/(2xx10^(-4) xx 1xx10^(-2)) = 10^(8)N//m^(2)`. |
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