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Two photons of energies twice and thrice the work function of a metal are incident on the metal surface. Then the ratio of maximum velocity of the photoelectrons emitted in the two cases respectively, isA. `sqrt2:1`B. `sqrt3:1`C. `sqrt3:2`D. `sqrt1:2` |
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Answer» Correct Answer - D `V_(1)/V_(2)=sqrt((E_(1)-omega_(0))/(E_(2)-omega_(0)))` |
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