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Two pipes A and B can fill a cistern in 30 minutes and 40 minutes respectibely. Both the pipes are opened. Find when the second pipe Bmust be turned off so the cistern may just be full in 10 minutes. |
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Answer» `26 2/3 min` WATERR filled in the period `= x (1/30 + 1/40) =(7X)/120` Remaining part `= 1- (7x)/120 + ((120-7x)/120)` Work done by A in `(10 - x)` minutes `= (120 -7x)/120 `= 1- (7x)/120 `(7x)/120 + (10-x)/30 =1 or 7 x + 40 - 4 x = 120 ` `3x= 120 - 40 = 80` `x= 26 2/3 min` |
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