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Two pipes A and B can fill a cistern in 8 hours and 12 hours respectively. The pipes when opened simultaneously takes 12 minutes more to fill the cistern due to leakage. Once the cistern is full, it will get emptied due to leakage in(a) 5 hrs.(b) 20 hrs.(c) 60 hrs.(d) 120 hrs. |
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Answer» Correct answer is: (d) 120 hrs. Portion of cistern filled by both pipes in 1 hour = \(\frac{1}{8}\)+\(\frac{1}{12}\) = \(\frac{5}{24}\) Time taken by both pipes to fill the cistern = 4 h 48 mints Time taken to fill tank due to leakage = 5 h Work done by leakage in 1 h = \(\frac{5}{24}\)- \(\frac{1}{5}\) = \(\frac{1}{20}\) |
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