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Two pipes A and B can fill a tank in 15 hours and 18 hours, respectively. Both pipes are opened simultaneously to fill the tank. In how many hours will the empty tank be filled?1. \(8 \dfrac{2}{11}\)2. \(7 \dfrac{2}{11}\)3. \(9 \dfrac{2}{11}\)4. \(10 \dfrac{2}{11}\) |
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Answer» Correct Answer - Option 1 : \(8 \dfrac{2}{11}\) Given: Pipe A can fill in 15 hours. Pipe B can fill in 18 hours. Calculation: Tank filled by Pipe A in 1 hour ⇒ 1/15 Tank filled by Pipe B in 1 hour ⇒ 1/18 Tank filled by both Pipes in 1 hour ⇒ (1/15) + (1/18) ⇒ 11/90 Time taken By both pipes to fill the tank ⇒ 90/11 \(\Rightarrow 8\frac{2}{{11}}\;{\rm{hours}}\) ∴ Time taken by both pipes is \(8\frac{2}{{11}}\;{\bf{hours}}\). |
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