Two pipes can fill a tank in 10 h and 16 h respectively. A third pipe – InterviewSolution

InterviewSolution

1.	Two pipes can fill a tank in 10 h and 16 h respectively. A third pipe can empty the tank in 32 h. If all the three pipes function simultaneously, then in how much time the tank will be full? (in hours)
Answer» `7 11/21` `7 13/21` `8 4/21` `6 5/14` Solution :10 HR A pipe `rarr 1` 16 hr B pipe `rarr 1` 32 hr C pipe `rarr 1` `1/10 + 1/16 - 1/32 = 21/160` `160/21 = 7 13/21 `hr Alternate Solution: Working together in 1 hour, they fill- `(16 +10 -5)` UNITS = 21 units `THEREFORE` Total time required `= 160/21 = 7 13/21` hours.

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