Two piston of a hydraulic lift have diameters of 60 cm and 5 cm. What is the force exerted by the larger piston when 50 N is placed on the smaller piston ?

Two piston of a hydraulic lift have diameters of 60 cm and 5 cm. What

1.	Two piston of a hydraulic lift have diameters of 60 cm and 5 cm. What is the force exerted by the larger piston when 50 N is placed on the smaller piston ?
Answer» Solution :SINCE, the diameter of the pistons are given, we can calculate the RADIUS of the piston `r = D/2` Area of SMALLER piston, `A_1 = pi(5/2)^(2) = pi(2.5)^(2)` Area of larger piston, `A_2 = pi(60/2)^2 = pi(30)^(2)` `F_2 = (A_2)/(A_1) xx F_1 = (50 N) xx (30/2.5)^2 = 7200 N` This means, with the force of 50 N, the force of 7200 N, can be LIFTED.