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Two plates are 1 cm apart and the potential difference between them is 10 V. The electric field between the plates is (a) 10 NC-1 (b) 250 NC-1(c) 500 NC-1(d) 1000 NC-1 |
Answer» Correct answer is (d) 1000 NC-1 Hint : E = \(\frac{V}{d}\) = \(\frac {10}{1 \times 10^{-2}}\) = 8.3 x 102 NC-1 |
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