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Two plates are 2 cm apart. If a potential difference of 10 V is applied between them. The electric field between the plates will be(a) 20 NC-1 (b) 500 NC-1 (c) 5 NC-1 (d) 250 NC-1 |
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Answer» Answer : 500 NC-1 Given : x = 2 cm V = 10V E = ? Solution : We know that , E = V/x = 10/2 × 10-2 = 5 × 102 = 500 NC-1 \(\therefore\) The electric field will be 500 NC-1 (b) 500 NC-1 \(\frac {V}{d}\)= \(\frac{10}{2 \times 10^{-2}}\) = 500 NC-1 |
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