1.

Two plates are `2cm` apart, a potential difference of `10` volt is applied between them, the electric field between the plates isA. `400N//C`B. `600N//C`C. `1000N//C`D. `800N//C`

Answer» Correct Answer - C
`E=V/d=10/10^(-2)=1000N//C`


Discussion

No Comment Found

Related InterviewSolutions