Saved Bookmarks
| 1. |
Two point charges +9e and +1e are kept at a distance of 16 cm from each other. At what point between these charges should a third charge q be placed so that it remains in equilibrium. |
|
Answer» Solution: Given charges: +e and +9e Let the third chare q be placed at a distance x from e and hence its distance from 9e is 16-x cm For the system to remain in equilibrium, F1 = F2 Therefore, F1 = K(e q)/x2 F2 = K(9e)/(16-x)2 Equating F1 and F2 , we get, 9/x2 = 1/(16-x)2 Taking square root on both sides: 3/x = 1/(16-x) Solving for x, we get, x = 12cm Hence, the charge q should be placed at 12 cm from +9e. |
|