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Two point charges of +5 µC are so placed that they experience a force of 80 × 10-3 N. They are then moved apart, so that the force is now 2.0 × 10-3 N. The distance between them is now (A) 1/4 the previous distance (B) double the previous distance (C) four times the previous distance (D) half the previous distance |
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Answer» Correct answer is (B) double the previous distance |
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