1.

Two point charges Q1 and Q2 placed at separation d in vacuum and force acting between them is F. Now a dielectric slab of thickness d2 and dielectric constant K=4 is placed between them. The new force between the charges will be

Answer»

Two point charges Q1 and Q2 placed at separation d in vacuum and force acting between them is F. Now a dielectric slab of thickness d2 and dielectric constant K=4 is placed between them. The new force between the charges will be



Discussion

No Comment Found

Related InterviewSolutions