 
                 
                InterviewSolution
 Saved Bookmarks
    				| 1. | Two point masses are connected by a light intextensible string are lying on a frictionless surface as shown in figure. An impulse of magnitude `10 kg-m//s` is given to `5 kg` block. A. Velocity of `10 kg` block immediately after impulse is given `(1)/(3) m//s`B. Velocity of `10 kg` block immediately after impulse is given `2 m//s`C. Speed of `5 kg` block immediately after impulse is given `sqrt((28)/(9)) m//s`D. Speed of `5 kg` block immediately after impulse is given `(sqrt(28))/(9) m//s` | 
| Answer» Correct Answer - A::C Along the string `10 cos 60^(circ) = (15)v_(x)` `rArr v_(x) = (1)/(3)m//s` for both `10 kg` and `5 kg`. In the direction perpendicular to string `10 sin 60^(circ) = 5v_(y) rArr v_(y) = sqrt(3) m//s` Velocity of `10 kg = (1)/(3) m//s`, velocity od `5 kg = sqrt(3+(1)/(9)) = (sqrt(28))/(3)m//s` | |