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Two point white dots are 1mm apart on a black paper. They are viewed by eye of pupil diameter 3mm. Approximately, what is the maximum distance at which these dits can be resolved by the eye? [Take wavelelngth of light =500nm]A. `5 m`B. `1 m`C. `6 m`D. `3 m` |
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Answer» Correct Answer - A (a) We know `(y)/(D) ge 1.22 (lambda)/(d)` `implies D le (y D)/(1.22 lambda) = (10^(-3) xx 3 xx 10^(-3))/(1.22 xx 5 xx 10^(-7))` `= (30)/(6.1) = 5 m :. D_(max) = 5 m` |
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