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Two points A and B are 2 cm apart and a uniform electric field E acts along the straight line `AB` directed A to B with `E=200N//C`. A particle of charge `+10^-6C` is taken from A to B along AB, Calculate a. the force on the charge b. the potential difference `V_A -V_B` and c.the work done on the charge by E |
Answer» Correct Answer - A::B::D a. Electrostatic force on the charge, `F=qE=(10^-6)(200)` `=2xx10^-4 N` b. In uniform electric field, `PD. V=E.d` or `V_A-V_B=200xx2xx10^-2` `=4V` c. `W(2xx10^-4)(2xx10^-2)cos0^@` `=4xx10^-6J` |
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