Two points are located at a distance of 10 m and 15 m from the source of wave. The period of oscillation is 0.05 sec and the velocity of the wave is 300 m/sec. What is the phase difference between the oscillations at two points ?.

Two points are located at a distance of 10 m and 15 m from the source

1.	Two points are located at a distance of 10 m and 15 m from the source of wave. The period of oscillation is 0.05 sec and the velocity of the wave is 300 m/sec. What is the phase difference between the oscillations at two points ?.
Answer» `pi/3` `(2pi)/(3)` `pi` `(pi)/(6)` Solution :For GIVEN wave, `v = f lamda = ( lamda)/(T)` `therefore lamda = v T = (300) (0.05) = 15 m` Phase difference between two PARTICLES separted by distance `Delta X` is, `DELTAPHI = (2pi)/(lamda) Delta x` `= (2pi)/(15) (15-10)` `= (2pi)/(3) rad `