Two projectile A and B located at (0,0) and (4.4) respectively start moving simu ltaneou lsy with velocities V_(A)=-4hati and V_(B)=4hatj:

Two projectile A and B located at (0,0) and (4.4) respectively start m

1.	Two projectile A and B located at (0,0) and (4.4) respectively start moving simu ltaneou lsy with velocities V_(A)=-4hati and V_(B)=4hatj:
Answer» the shortest DISTANCE between them is `4sqrt(2)m` the shortest distance between them first decreases and then increases the distance between them increases from the beginning the magnitude of relative velocity of A w.r.t. B is 4m/s Solution :Horizontal range =VxxT Since the 2nd PARTICLE is projected after 2s. Hence the particles will reach the ground in an INTERVAL of 2s.