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Two projectiles are projected with velocity `v_(A), v_(B)` at angles `theta_(A)` (from horizontal) and `theta_(B)` (from vertical) as shown in the figure below, such that `v_(A) gt v_(B)` but having same horizontal component of velocity. Which of the following can be correct ? A. `T_(A) gt T_(B)`B. `H_(A) gt H_(B)`C. `R_(A) gt R_(B)`D. `R_(B) gt R_(A)` |
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Answer» Correct Answer - A::B::C `v_(AX)=v_(BX)` `v_(Ay)^(2)+v_(Bx)^(2)gtv_(By)^(2)+v_(Bx)^(2)` `thereforev_(Ay)gtv_(By)` `R=(2v_(x)v_(y))/(g)" "thereforeR_(A) gtR_(B)` `H=(2v_(y)^(2))/(g)" "thereforeH_(A)gtH_(B)` `T=(2v_(y))/(g)" "thereforeT_(A)gtT_(B)` |
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