Two protons of masses 1.6×10−27 kg, goes round in a concentric circular orbits of radii 0.50 nm and 1 nm experience centripetal forces in the ratio of 1:4, then the ratio of frequency of revolution of the protons is (Assume no force of interaction between protons )

Two protons of masses 1.6×10−27 kg, goes round in a concentric circ

1.	Two protons of masses 1.6×10−27 kg, goes round in a concentric circular orbits of radii 0.50 nm and 1 nm experience centripetal forces in the ratio of 1:4, then the ratio of frequency of revolution of the protons is (Assume no force of interaction between protons )
Answer» Two protons of masses $1.6 \times 10^{- 27} kg$ , goes round in a concentric circular orbits of radii $0.50 nm$ and $1 nm$ experience centripetal forces in the ratio of $1 : 4$ , then the ratio of frequency of revolution of the protons is (Assume no force of interaction between protons )

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Two protons of masses 1.6×10−27 kg, goes round in a concentric circular orbits of radii 0.50 nm and 1 nm experience centripetal forces in the ratio of 1:4, then the ratio of frequency of revolution of the protons is (Assume no force of interaction between protons )

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