InterviewSolution
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InterviewSolution
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Two protons parallel to each other, keeping distane r between them, both moving with same velocity `vecV` Then the ratio of the electric is magnetic force of interaction between them is .A. `c^(2)//V^(2)`B. `2c^(2)//V^(2)`C. `c^(2)//2V^(2)`D. None |
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Answer» Correct Answer - A `F_(e) = (Kq^(2))/(r^(2)) = (1)/(4pi in_(0)) (q^(2))/(r^(2))` `F_(m) = (mu_(0))/(4pi) (q_(1)q_(2)V^(2))/(r^(2)) = (mu_(0))/(4pi) (q^(2)V^(2))/(r^(2))` `(F_(e))/(F_(m)) = (1)/(mu_(0) in_(0)) . (1)/(V^(2)) = (C^(2))/(V^(2))` . |
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