1.

Two radio-isotopes P and Q of atomic weight 10 and 20 respetively are mixedratio is found to be 1:m 4 Isotope P has a half-life of 10 day The half of isotope Q is:

Answer»

Zero
`5` day
`20` day
Infinite

Solution :Let `WG` of each be taken then
Initial mole of `P = (w)/(10)`, mole of `Q = (w)/(20)`
Final mole of `P = (w_(1))/(5xx10)`
Final mole of `Q = (4w_(1))/(20xx5)`
For P, `(P_(N_(0)))/(P_(N))=e^(lambda_(1)t)`
For `Q, (Q_(N_(0)))/(Q_(N))=e^(lambda_(2)t)`
For `P :. (w xx 5 xx10)/(10xx w_(1)) = e^(lambda_(1) xx20)` ...(i)
For `Q :. (w xx 20xx5)/(20XX w_(1) xx4) = e^(lambda_(1) xx20)` ...(ii)
By (i) and (ii), `4 = e^(lambda_(1) - lambda_(2)xx20)`
`:. 20(lambda_(1) - lambda_(2)) = log_(e) 4`
`:. t = oo`


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