Two reactionshaving their energy of activation E_(1) and E_(2) temperature coefficients T_(c_(1)) and T_(c_(2)) respectively within the temperature 300 and 310K. The ratio of their temperature coefficient is:

Two reactionshaving their energy of activation E_(1) and E_(2) tempera

1.	Two reactionshaving their energy of activation E_(1) and E_(2) temperature coefficients T_(c_(1)) and T_(c_(2)) respectively within the temperature 300 and 310K. The ratio of their temperature coefficient is:
Answer» `e^(E_(1)//E_(2))` `e^((E_(1)-E_(2))xx10^(-4)//R)` `10^(E_(1)//E_(2))` `e^((E_(1) - E_(2))//4)` SOLUTION :`2.303 logt_(C_(1)) = (E_(1))/(R) [(T_(2) - T_(1))/(T_(1) T_(2))]` `2.303 log T_(c_(2)) = (E_(2))/(R) [(T_(2) - T_(1))/(T_(1) T_(2))]` `2.303 [log T_(C_(1)) - log T_(C_(2))]` `= ((E_(1) - E_(2)))/(R) xx [(310 - 300)/(300xx310)]` `:. 2.303 log ((T_(C_(1)))/(T_(C_(2)))) = [(E_(1) - E_(2))/(R)] xx 1.07xx10^(-4)` or In `(T_(c_(1)))/(T_(C_(2))) = [(E_(1) - E_(2))/R] xx 10^(-4)` `:. (T_(c_(1)))/(T_(c_(2))) = e^([(E_(1) - E_(2))/(R)]xx10^(-4))`