1.

Two resistance wires are made up of same material and have same length. If ratio of areas of cross section is 2:11 then what is the ratio of their resistance?

Answer»

We know that;

R = K x \(\frac { 1 }{ A }\)

If R1 and R2 are resistance of two wires and and A2 are their areas of cross section then,

\(\frac { { R }_{ 1 } }{ { R }_{ 2 } }\) = \(\frac { l }{ { A }_{ 1 } }\) +\(\frac { l }{ { A }_{ 2 } }\)

\(\frac { { A }_{ 2 } }{ { A }_{ 1 } }\) = \(\frac { 11 }{ 2 }\)


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