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Two Rods of same cross sectional area and same length but different thermal conductivity `K_(1)` and `K_(2)` are first connected in series and then connected in parallel between same temperature difference in both cases Then the ratio of rates of heat flow in both cases is.A. `(4k_(1)k_(2))/((k_(1)+k_(2))^(2))`B. noneC. `((k_(1)+k_(2))/(k_(1)-k_(2)))`D. `(k_(1)k_(2))/((k_(1)+k_(2))^(2))` |
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Answer» Correct Answer - B `y=Asin(kx-omegat)` `(v_("particle"))_("max")=Aomega=(2piAV)/(lambda)` wave speed `=v=(omega)/(k)` |
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