Two samples of water A and B having concentration 16.2 ppm of Ca(HCO_(3))_(2) and 13.6 pp m of CaCl_(2) respectively. Then

Two samples of water A and B having concentration 16.2 ppm of Ca(HCO_(

1.	Two samples of water A and B having concentration 16.2 ppm of Ca(HCO_(3))_(2) and 13.6 pp m of CaCl_(2) respectively. Then
Answer» Hardness is more in 'B' sample than in 'A' Hardness is more in 'A' sample than in 'B' Hardness is same in both cases Hardness in sample 'B' is TWICE that of the sample 'A' Solution :A = 16.2 g of `CaHCO_3` B = 13.6 g of `CaCl_2` hardness of `A = 16.2 XX 100/162 = 10` PPM hardnessof `B = 13.6 xx 100/111=12.25` ppm