Two satellite A and B, ratio of masses 3:1 are in circular orbits of radii r and 4r. Then ratio mechanical energy of A and B is

Two satellite A and B, ratio of masses 3:1 are in circular orbits of r

1.	Two satellite A and B, ratio of masses 3:1 are in circular orbits of radii r and 4r. Then ratio mechanical energy of A and B is
Answer» `1:3` `3:1` `3:4` `12:1` Solution :Energy of SATELLITE is given by `E=-(GMm)/(2r)or E prop (m)/(r)` `rArr (E_(A))/(E_(B))=(m_(A))/(m_(B))XX(r_(B))/(r_(A))=(3)/(1)xx(4r)/(r)""{because (m_(A))/(m_(B))=(3)/(1),(r_(B))/(r_(A))=(4r)/(r)}` `rArr (E_(A))/(E_(B))=(12)/(1)`.