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Two similarspringsP and Q have springconstant k_(p) and k_(Q) such that k_(p) gt k_(Q) . They are stretched , first by the same amount (case a,) then by the same force (case b ) . The work done by the springs W_(P) and W_(Q) are related as , in case (a) and case (b) , respectively : |
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Answer» `W_(P) =W_(Q),W_(P)gt W_(Q)` `(W_(P))/(W_(Q))=(1/2k_(P)x^(2))/(1/2K_(Q)x^(2))=(K_(P))/(K_(Q))` But `K_(P) gt K_(Q)` is given , ` :. W_(P) gt W_(Q)` For Case (b) : `F_(1) = F_(2) = F ` For constant FORCE `W = (F^(2))/(2K):. W prop 1/K ` ` :. (W_(P))/(W_(Q)) = (K_(Q))/(K_(P))` but , `K_(P) gt K_(Q) rArr W_(P) lt W_(Q)` ` :. W_(Q) gt W_(P)` . |
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